Optimal. Leaf size=239 \[ \frac{2 \left (a^3 A+9 a^2 b B+9 a A b^2+b^3 B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} \text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )}{3 d}-\frac{2 b \left (2 a^2 A-9 a b B-3 A b^2\right ) \sin (c+d x) \sqrt{\sec (c+d x)}}{3 d}+\frac{2 \left (3 a^2 A b+a^3 B-3 a b^2 B-A b^3\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{d}-\frac{2 b^2 (a A-b B) \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x)}{3 d}+\frac{2 a A \sin (c+d x) (a+b \sec (c+d x))^2}{3 d \sqrt{\sec (c+d x)}} \]
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Rubi [A] time = 0.510185, antiderivative size = 239, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.212, Rules used = {4025, 4076, 4047, 3771, 2641, 4046, 2639} \[ -\frac{2 b \left (2 a^2 A-9 a b B-3 A b^2\right ) \sin (c+d x) \sqrt{\sec (c+d x)}}{3 d}+\frac{2 \left (a^3 A+9 a^2 b B+9 a A b^2+b^3 B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{3 d}+\frac{2 \left (3 a^2 A b+a^3 B-3 a b^2 B-A b^3\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{d}-\frac{2 b^2 (a A-b B) \sin (c+d x) \sec ^{\frac{3}{2}}(c+d x)}{3 d}+\frac{2 a A \sin (c+d x) (a+b \sec (c+d x))^2}{3 d \sqrt{\sec (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 4025
Rule 4076
Rule 4047
Rule 3771
Rule 2641
Rule 4046
Rule 2639
Rubi steps
\begin{align*} \int \frac{(a+b \sec (c+d x))^3 (A+B \sec (c+d x))}{\sec ^{\frac{3}{2}}(c+d x)} \, dx &=\frac{2 a A (a+b \sec (c+d x))^2 \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}-\frac{2}{3} \int \frac{(a+b \sec (c+d x)) \left (-\frac{1}{2} a (7 A b+3 a B)-\frac{1}{2} \left (a^2 A+3 A b^2+6 a b B\right ) \sec (c+d x)+\frac{3}{2} b (a A-b B) \sec ^2(c+d x)\right )}{\sqrt{\sec (c+d x)}} \, dx\\ &=-\frac{2 b^2 (a A-b B) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}+\frac{2 a A (a+b \sec (c+d x))^2 \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}-\frac{4}{9} \int \frac{-\frac{3}{4} a^2 (7 A b+3 a B)-\frac{3}{4} \left (a^3 A+9 a A b^2+9 a^2 b B+b^3 B\right ) \sec (c+d x)+\frac{3}{4} b \left (2 a^2 A-3 A b^2-9 a b B\right ) \sec ^2(c+d x)}{\sqrt{\sec (c+d x)}} \, dx\\ &=-\frac{2 b^2 (a A-b B) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}+\frac{2 a A (a+b \sec (c+d x))^2 \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}-\frac{4}{9} \int \frac{-\frac{3}{4} a^2 (7 A b+3 a B)+\frac{3}{4} b \left (2 a^2 A-3 A b^2-9 a b B\right ) \sec ^2(c+d x)}{\sqrt{\sec (c+d x)}} \, dx-\frac{1}{3} \left (-a^3 A-9 a A b^2-9 a^2 b B-b^3 B\right ) \int \sqrt{\sec (c+d x)} \, dx\\ &=-\frac{2 b \left (2 a^2 A-3 A b^2-9 a b B\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{3 d}-\frac{2 b^2 (a A-b B) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}+\frac{2 a A (a+b \sec (c+d x))^2 \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}-\left (-3 a^2 A b+A b^3-a^3 B+3 a b^2 B\right ) \int \frac{1}{\sqrt{\sec (c+d x)}} \, dx-\frac{1}{3} \left (\left (-a^3 A-9 a A b^2-9 a^2 b B-b^3 B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)}} \, dx\\ &=\frac{2 \left (a^3 A+9 a A b^2+9 a^2 b B+b^3 B\right ) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{3 d}-\frac{2 b \left (2 a^2 A-3 A b^2-9 a b B\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{3 d}-\frac{2 b^2 (a A-b B) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}+\frac{2 a A (a+b \sec (c+d x))^2 \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}-\left (\left (-3 a^2 A b+A b^3-a^3 B+3 a b^2 B\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \sqrt{\cos (c+d x)} \, dx\\ &=\frac{2 \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right ) \sqrt{\cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{d}+\frac{2 \left (a^3 A+9 a A b^2+9 a^2 b B+b^3 B\right ) \sqrt{\cos (c+d x)} F\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{\sec (c+d x)}}{3 d}-\frac{2 b \left (2 a^2 A-3 A b^2-9 a b B\right ) \sqrt{\sec (c+d x)} \sin (c+d x)}{3 d}-\frac{2 b^2 (a A-b B) \sec ^{\frac{3}{2}}(c+d x) \sin (c+d x)}{3 d}+\frac{2 a A (a+b \sec (c+d x))^2 \sin (c+d x)}{3 d \sqrt{\sec (c+d x)}}\\ \end{align*}
Mathematica [A] time = 1.98562, size = 166, normalized size = 0.69 \[ \frac{\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)} \left (2 \left (a^3 A+9 a^2 b B+9 a A b^2+b^3 B\right ) \text{EllipticF}\left (\frac{1}{2} (c+d x),2\right )+6 \left (3 a^2 A b+a^3 B-3 a b^2 B-A b^3\right ) E\left (\left .\frac{1}{2} (c+d x)\right |2\right )+\frac{\sin (c+d x) \left (a^3 A \cos (2 (c+d x))+a^3 A+6 b^2 (3 a B+A b) \cos (c+d x)+2 b^3 B\right )}{\cos ^{\frac{3}{2}}(c+d x)}\right )}{3 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 5.698, size = 1212, normalized size = 5.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{B b^{3} \sec \left (d x + c\right )^{4} + A a^{3} +{\left (3 \, B a b^{2} + A b^{3}\right )} \sec \left (d x + c\right )^{3} + 3 \,{\left (B a^{2} b + A a b^{2}\right )} \sec \left (d x + c\right )^{2} +{\left (B a^{3} + 3 \, A a^{2} b\right )} \sec \left (d x + c\right )}{\sec \left (d x + c\right )^{\frac{3}{2}}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B \sec \left (d x + c\right ) + A\right )}{\left (b \sec \left (d x + c\right ) + a\right )}^{3}}{\sec \left (d x + c\right )^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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